X^2+2x+4x=624

Solution for X^2+2x+4x=624 equation:

X^2+2X+4X=624

We move all terms to the left:

X^2+2X+4X-(624)=0

We add all the numbers together, and all the variables

X^2+6X-624=0

a = 1; b = 6; c = -624;
Δ = b2-4ac
Δ = 62-4·1·(-624)
Δ = 2532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2532}=\sqrt{4*633}=\sqrt{4}*\sqrt{633}=2\sqrt{633}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{633}}{2*1}=\frac{-6-2\sqrt{633}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{633}}{2*1}=\frac{-6+2\sqrt{633}}{2}
$